Final Answer:
Drew's rectangle should have a length of 10 centimeters.
Step-by-step explanation:
Ms. Kochhar provided a length to width ratio of 5 to 3 for the rectangle drawn on the chalkboard. This means that for every 5 units of length, there are 3 units of width. Given that Drew plans to draw a rectangle with a width of 6 centimeters, we can use the ratio to find the corresponding length.
To find the length, we can set up a proportion using the given ratio:
![\[ (5)/(3) = \frac{\text{Length}}{\text{Width}} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/pg5gvb5aamaziwipk6au63mvu8dg0bd50h.png)
Substituting the known values, where the width is 6 centimeters:
![\[ (5)/(3) = \frac{\text{Length}}{6} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/tkvg6cdkhexczwp9zh48tghmciavqne2lu.png)
Cross-multiplying to solve for the length:
![\[ 5 * 6 = 3 * \text{Length} \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/n2bl9tas8w32wq8xs2uj0d81ztdc7dws0s.png)
![\[ \text{Length} = (5 * 6)/(3) \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/w4hbklunu06k7v3ggqeu09c6ll3m3qq7nf.png)
![\[ \text{Length} = 10 \]](https://img.qammunity.org/2024/formulas/mathematics/high-school/mekjwzdtwotsu3w77v3u42pwwy5vdgst2v.png)
Therefore, Drew's rectangle should have a length of 10 centimeters to maintain the given ratio of 5 to 3.
In conclusion, by understanding the concept of ratios and setting up a proportion, we determined that the length of Drew's rectangle should be 10 centimeters.
This method allows for a straightforward and precise way to find the corresponding length when given a specific width-to-length ratio. It's a fundamental mathematical approach applicable in various real-life scenarios involving proportional relationships.