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9s2 4s–6=0 How many real solutions does the equation have?

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Final answer:

The equation 9s^2 + 4s - 6 = 0 has a positive discriminant, which indicates that it has two real solutions.

Step-by-step explanation:

To determine the number of real solutions of the equation 9s^2 + 4s - 6 = 0, we can use the discriminant from the quadratic formula, which is part of the expression under the square root sign: b^2 - 4ac. In our equation, a = 9, b = 4, and c = -6. Let's calculate the discriminant:

  • b^2 - 4ac = (4)^2 - 4(9)(-6).
  • b^2 - 4ac = 16 + 216.
  • b^2 - 4ac = 232.

Since the discriminant is positive, the quadratic equation has two real solutions.

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