Question

For the reaction: 3 O₂ (g) 2O, (g) K=1.8 x 10ˣ. If the equilibrium concentration [O₂] = 0.062 mol/L, calculate the equilibrium O₂ concentration.

Answer 1

For the reaction: 3 O₂ (g) 2O, (g) K=1.8 x 10ˣ, the equilibrium [O₂] concentration is approximately 0.0065 mol/L.

Step-by-step explanation:

To calculate the equilibrium O₂ concentration, we need to use the equilibrium expression and the given equilibrium concentration of [O₂]. The balanced reaction is:

3O₂ (g) ⇌ 2O, (g)

The equilibrium expression is K = [O,]² / [O₂]³. Given that K = 1.8 x 10^x, we can plug in the values:

1.8 x 10^x = (2x)² / (0.062)³

Simplifying the equation, we get:

1.8 x 10^x = 4x² / 0.238

Now, we can solve for x:

0.238 × 1.8 x 10^x = 4x²

We solve for x using quadratic equations or approximation methods:

x ≈ 0.0065

Therefore, the equilibrium [O₂] concentration is approximately 0.0065 mol/L.