Final answer:
The minimum mass of a fish to be safe for consumption with 5.02 mg of PCBs, using the legal limit of 2.00 ppm, is calculated to be 2.510 kg.
Step-by-step explanation:
The question asks for the minimum mass of a fish that would be safe to eat if it contains 5.02 mg of PCBs, given that the legal limit is 2.00 ppm. To calculate this, we use the formula:
Concentration (ppm) = (mass of substance (mg) / mass of sample (g)) × 106
First, we convert the concentration from ppm to mg/g:
2.00 ppm = 2.00 mg of PCBs per 1000 g of fish
Using cross-multiplication:
2.00 mg / 1000 g = 5.02 mg / x g
Where x is the mass of the fish in grams. Solving for x gives us:
x = (5.02 mg × 1000 g) / 2.00 mg
x = 2510 g or 2.510 kg
Therefore, the minimum mass of the fish required to have a PCB level of less than 2.00 ppm would be 2.510 kg.