The monthly payments and the total costs are
- $1,531.29 and $551264.40
- $1,531.29 and $1339664.40
How to determine the payments and the total cost
a) 7 1/2 % compounded monthly with no points
Here, we have
The monthly interest rate is 7.5%/12 = 0.625%.
The number of monthly payments is 30 years * 12 months/year = 360 months.
So, the monthly payment can be calculated using the formula:
![M = (P[i(1 + i)^n])/((1 + i)^n - 1)](https://img.qammunity.org/2024/formulas/mathematics/college/fyf6pgm8duzfwzojszp05vcmnexhm7l3px.png)
Where:
- M is the monthly payment
- P is the principal amount ($219,000.00)
- i is the monthly interest rate (0.625%)
- n is the number of payments (360)
Substitute the known values into the equation
![M = (219000 * [0.00625 * (1 + 0.00625)^(360)])/((1 + 0.00625)^(360) - 1)](https://img.qammunity.org/2024/formulas/mathematics/college/baxhyj2vnh6oj7cgo9stha6mghp6lxllwr.png)
M = $1,531.29
For the total cost, we have
Total cost = $1,531.29/month * 360 months
Total cost = $551264.40
b) 7 1/4 % compounded monthly with 1 point
Here, we have
One point is equal to 1% of the mortgage amount, so buying one point would cost $2,190.00.
The other parameters remain the same
So:
![M = (219000 * [0.00625 * (1 + 0.00625)^(360)])/((1 + 0.00625)^(360) - 1)](https://img.qammunity.org/2024/formulas/mathematics/college/baxhyj2vnh6oj7cgo9stha6mghp6lxllwr.png)
M = $1,531.29
For the total cost, we have
Total cost = ($1,531.29 + $2190.00)/month * 360 months
Total cost = $1339664.40