225k views
0 votes
Which is a stretch of an exponential decay function? 1) f(x) = Four-fifths (five-fourths)ˣ 2) f(x) = Four-fifths (four-fifths)ˣ 3) f(x) = Five-fourths (four-fifths)ˣ 4) f(x) = Five-fourths (five-fourths)ˣ

User Gilad Hoch
by
6.7k points

1 Answer

1 vote

Final answer:

The exponential decay function is represented by f(x) = Four-fifths (five-fourths)^x.

The answer is option ⇒1

Step-by-step explanation:

The exponential decay function f(x) = Four-fifths (five-fourths)^x represents a decay process where the value of the function decreases as x increases.

Let's break down the function step-by-step:

1. The base of the exponential function is (five-fourths). This means that the value of (five-fourths)^x is repeatedly multiplied by itself as x increases.

2. The coefficient of the exponential function is Four-fifths. This means that the value of the exponential function is multiplied by Four-fifths.

3. The overall effect of the function is decay. As x increases, the value of the exponential term (five-fourths)^x decreases, and then it is multiplied by Four-fifths, further decreasing the value.

For example, let's evaluate the function at x = 1:

f(1) = Four-fifths (five-fourths)^1

Calculating (five-fourths)^1 gives us (5/4)^1 = 5/4.

Multiplying (5/4) by Four-fifths gives us (4/5) * (5/4) = 1.

So, f(1) = 1.

This means that when x = 1, the function has a value of 1.

In general, as x increases, the value of the function f(x) will decrease due to the exponential decay behavior of the function.

The answer is option ⇒1

User Mareoraft
by
8.2k points