Question

Supply a ‘recipe’ for making 5.000 L of 0.01234 M NaOH solution. You have access to a starting solution of NaOH in water that was made by adding 45.67 g NaOH to a 2.000 L volumetric flask and making it up to the 2.000 L mark with water. How much NaOH solution do you need to add into a 5L volumetric flask? 2 points 0.5710 L 0.5710 ml/L 0.1081 L 0.0216 L

Answer 1

To prepare 5 L of 0.01234 M NaOH solution, you need to mix 0.1081 L of the initial 0.570875 M NaOH solution into a 5L flask and dilute it with water to the mark. So the correct answer is Option 3.

Step-by-step explanation:

To prepare a 5.000 L of 0.01234 M NaOH solution from a starting solution that was made by adding 45.67 g NaOH to a 2.000 L volumetric flask, we first need to calculate the molarity of the starting solution. With the molar mass of NaOH being approximately 40 g/mol, the number of moles of NaOH in the starting solution is:

moles NaOH = 45.67 g / 40 g/mol = 1.14175 mol

Thus, the molarity (M) of the starting solution is:

Molarity = moles/volume = 1.14175 mol / 2.000 L = 0.570875 M

Next, we use the dilution formula M1V1 = M2V2, where M1 is the molarity of the initial solution, V1 is the volume of the initial solution needed, M2 is the final molarity, and V2 is the final volume.

0.570875 M * V1 = 0.01234 M * 5.000 L

V1 = (0.01234 M * 5.000 L) / 0.570875 M = 0.1081 L of the starting NaOH solution

To make the desired 5 L of 0.01234 M NaOH solution, you would need to add 0.1081 L of the starting 0.570875 M NaOH solution to a 5L volumetric flask and add water to reach the 5 L mark.