Question

A 330N box is resting on the floor. The coefficient of static friction is 0.8 and the coefficient of kinetic friction is 0.45. Nomas is able to push the box with enough force to make the box start sliding across the floor. How much force must Nomas apply to the box to keep the box moving?

Answer 1

Nomas must apply a force greater than the force of kinetic friction, which is 148.5 N, to keep the box moving.

Step-by-step explanation:

To find the force required to keep the box moving, we need to consider the coefficient of kinetic friction.

Given that the coefficient of kinetic friction is 0.45, the force of kinetic friction (f`k) can be calculated using the equation f`k = μk N, where μk is the coefficient of kinetic friction and N is the normal force.

The normal force is equal to the weight of the box, which can be calculated as N = mg, where m is the mass of the box and g is the acceleration due to gravity.

Substituting the given values, the force of kinetic friction is f`k = (0.45)(330 N) = 148.5 N.

Therefore, Nomas must apply a force greater than the force of kinetic friction, which is 148.5 N, to keep the box moving.