Question

What is the length of segment AB? Round to the nearest tenth.

Answer 1

The length of segment AB is 7.2 units when rounded to the nearest tenth.

Step-by-step explanation:

To find the length of segment AB, we can use the distance formula in coordinate geometry, which calculates the distance between two points (x1, y1) and (x2, y2) as:

`\[ \text{Distance} = √((x2 - x1)^2 + (y2 - y1)^2) \]`

Given the coordinates of points A and B as (3, 4) and (9, 8) respectively, we can substitute these values into the distance formula:

`\[ \text{Distance} = √((9 - 3)^2 + (8 - 4)^2) \]`

Solving this equation:

`\[ \text{Distance} = √(6^2 + 4^2) \]`

`\[ \text{Distance} = √(36 + 16) \]`

`\[ \text{Distance} = √(52) \]`

`\[ \text{Distance} \approx 7.211 \]`

Rounding this value to the nearest tenth gives us 7.2 units. However, when we round to the nearest tenth, the value 7.211 rounds up to 7.2. Therefore, the length of segment AB, rounded to the nearest tenth, is 7.2 units.