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A large rectangular city pool is twice as long and twice as wide as a small rectangular pool the small pool is 12 feet long with a perimeter of 38 feet what is the area of the large city pool

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Final answer:

The area of the large city pool, which has doubled dimensions compared to a smaller pool with a length of 12 feet and perimeter of 38 feet, is calculated to be 336 square feet.

Step-by-step explanation:

The question asks for the area of a large city pool which is twice as long and twice as wide as a smaller pool. First, we determine the dimensions of the smaller pool. With a length of 12 feet and a perimeter of 38 feet, we can calculate the width:

Perimeter of a rectangle = 2(length + width)

38 = 2(12 + width)

19 = 12 + width

Width = 19 - 12

Width = 7 feet

Now, for the larger pool, the dimensions are doubled, so the length is 12 feet x 2 = 24 feet, and the width is 7 feet x 2 = 14 feet. To find the area, multiply length by width:

Area of large pool = length x width

Area of large pool = 24 feet x 14 feet

Area of large pool = 336 square feet

The answer is that the area of the large city pool is 336 square feet.

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