Question

What is the value of V in liters when 15.0 grams of powdered mixture X, consisting of KHCO₃ and CaCO₃, is completely dissolved in 500 ml of 0.5 M H₂SO₄ solution to produce gas (dktc) and solution Y? To neutralize the excess acid in Y, a solution containing a mole of NaOH is required. Calculate the value of V.

Answer 1

To calculate the value of V, you need to determine the number of moles of KHCO₃ and CaCO₃ in the powdered mixture X. By calculating the moles of each compound and using the mole ratio between the compounds and H₂SO₄4, you can find the volume needed to neutralize the excess acid. So, the volume is 239 mL.

Step-by-step explanation:

To calculate the value of V, we need to determine the number of moles of KHCO₃ and CaCO₃ in the powdered mixture X. First, calculate the number of moles of KHCO₃ using its molar mass (39.10 g/mol):

Moles of KHCO₃ = 15.0 g / 39.10 g/mol = 0.383 mol KHCO₃

Next, calculate the number of moles of CaCO3 using its molar mass (100.09 g/mol):

Moles of CaCO₃ = 15.0 g / 100.09 g/mol = 0.150 mol CaCO3

The total volume of solution Y is 500 mL + V (in liters). Since the mole ratio between KHCO₃ and H₂SO₄ is 1:2, and the mole ratio between CaCO₃ and H₂SO₄4 is also 1:2, we can set up the following equation:

(0.383 mol KHCO₃ / 2) + (0.150 mol CaCO₃ / 2) = (0.5 M H2SO4) * (500 mL + V)

Solving the equation for V, we find:

V = 0.239 L or 239 mL