Final answer:
The 32N force acting at a 30° angle with the horizontal has a horizontal component of approximately 27.71N and a vertical component of 16N, calculated using trigonometric functions.
Step-by-step explanation:
The student's question involves finding the resolving parts or components of a force that is inclined to the horizontal. When a 32N force acts along a straight line AB at an angle of 30° with the horizontal, this force has two components: a horizontal component (Fx) and a vertical component (Fy). The horizontal component can be found by multiplying the force by the cosine of the angle (Fx = F × cos(θ)) and the vertical component by multiplying the force by the sine of the angle (Fy = F × sin(θ)). Thus, for a 32N force at 30°:
Fx = 32N × cos(30°)
Fy = 32N × sin(30°)
To find the values:
Fx = 32N × (√3/2) ≈ 27.71N
Fy = 32N × (1/2) = 16N
So, the 32N force at 30° with the horizontal has a horizontal component of approximately 27.71N and a vertical component of 16N.