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Consider the function f(x) = 3 / x - 2. State the equation of the vertical asymptote. Use a table of values to determine the behaviour(s) of the function. State the equation of the horizontal asymptote. Use a table of values to determine the end behaviours of the function near its horizontal asymptote. Determine the domain and range. Determine the positive and negative intervals. Sketch the graph.

User Nandini
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The function f(x) has a vertical asymptote at x = 2 and the Horizontal Asymptotes is y = 0

Vertical Asymptotes

From the question, we have the following parameters that can be used in our computation:

f(x) = 3/(x - 2)

The denominator of the function, x - 2,

This means, that f(x) has a vertical asymptote at x = 2.

Behavior near the Vertical Asymptotes

As x approaches 2 from the left, f(x) approaches negative infinity.

As x approaches 2 from the right, f(x) approaches positive infinity.

Horizontal Asymptote

Here, the Horizontal Asymptotes is y = 0

This is so because the degree of the numerator is less than the degree of the denominator

End Behavior

As x approaches positive infinity, f(x) approaches 0.

As x approaches negative infinity, f(x) approaches 0.

Domain

The function f(x) is undefined when the denominator, x - 2, is equal to zero.

So, the domain of the function is all real numbers except for x = 2.

Range

The range of the function f(x) is all real numbers less than 0 and greater than or equal to 0.

This is because the function cannot take 0 as its value

Positive and Negative Intervals

The function f(x) is positive when x is greater than 2

The function f(x) is negative when x is less than 2

Consider the function f(x) = 3 / x - 2. State the equation of the vertical asymptote-example-1
User Junior Jiang
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