so the quadratic has roots or x-intercepts at 2 and 10, or namely it has zeros when x = 2 and x = 10, whilst it passes through (4 , -3).
Now, let's reword all that
what's the equation of a quadratic whose roots are 2 and 10 and it passes through (4 , -3)?
![\begin{cases} x = 2 &\implies x -2=0\\ x = 10 &\implies x -10=0 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{original~polynomial}{a ( x -2 )( x -10 ) = \stackrel{0}{y}} \hspace{5em}\textit{we also know that } \begin{cases} x=4\\ y=-3 \end{cases} \\\\\\ a ( 4 -2 )( 4 -10 ) = -3\implies a(2)(-6)=-3\implies -12a=-3 \\\\\\ a=\cfrac{-3}{-12}\implies a=\cfrac{1}{4} \\\\[-0.35em] ~\dotfill](https://img.qammunity.org/2024/formulas/mathematics/college/p6sdyevqwaedrtozpqpu1kccm11rnjzqbc.png)

Check the picture below.