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Spinner A has green, yellow and red sections. Spinner B has green and yellow sections only. Olivia spins each spinner once. Work out how many possible ways there are for at least one of the spinners to land on green. (Hint: copy and complete the tree diagram first.) Spinner A Spinner B

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User Sayan Pal
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There are 4 possible ways for at least one of the spinners to land on green.

Working out the possible ways there to get at least one green

From the question, we have the following parameters that can be used in our computation:

Spinner A has green, yellow and red sections.

Spinner B has green and yellow sections

When both spinners are spun once, we have the following outcomes

GG, GY, YG, YY, RG, RY

Where

Green = G, Yellow = Y and Red = R

The outcomes that have at least one green are

GG, GY, YG, and RG

This means that there are 4 possible ways to get at least one green

User WpfBee
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