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Give the vertex and axis of symmetry of each quadratic funct f(x)=(x+1)^(2)-8

User Autoflyer
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Final answer:

The vertex of the quadratic function is (-1, -8) and the axis of symmetry is x = -1.

Step-by-step explanation:

The given quadratic function is f(x) = (x+1)² - 8.

To find the vertex, we need to identify the values of x and y that make the function minimum or maximum. This occurs at the vertex.

The x-coordinate of the vertex can be found by using the formula x = -b/2a

where a and b are the coefficients of x² and x, respectively.

In this case, a = 1 and b = 2,

so x = -2/2

x= -1.

To find the y-coordinate of the vertex, substitute the x-coordinate into the function.

f(-1) = (-1+1)² - 8

= 0 - 8

= -8.

Therefore, the vertex is (-1, -8). The axis of symmetry is a vertical line that passes through the vertex. In this case, the axis of symmetry is the line x = -1.

User Tabriz Atayi
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