Question

Itial velocity of 176 feet per s ctionh (t)=-16t^(2)+176t+2

Answer 1

The question is about High School level Physics, focusing on motion and kinematics, where one calculates velocity and acceleration from a provided position function of an object's motion over time.

Step-by-step explanation:

The subject of this question is Physics, specifically focusing on kinematics, which includes the study of motion with respect to displacement, velocity, and acceleration without considering the causes of motion. The grade level of this question is High School, where students learn to interpret and solve problems related to motion.

To address the question given, which provides a position function h(t) = -16t2 + 176t + 2, first, we need to understand that the position function represents the height h of an object (likely a projectile in this case) as a function of time t. The initial velocity can be found by taking the derivative of the position function with respect to time, which would yield the velocity function. The coefficient of the t-term in the velocity function represents the initial velocity of the object.

To find the acceleration, we would look at the coefficient of the t2 term in the original position function. In this case, acceleration due to gravity is represented as -16 feet per second squared in the position function. Average velocity and instantaneous velocity can be calculated using the position function and its derivative respectively.

Answer 2

The projectile's height above the ground after 2 seconds, if its height h(t) above the ground is given by the function h(t) = -16t² + 176t, is 288 feet.

Step-by-step explanation:

The question involves calculating the height of a projectile after a certain amount of time has passed given its initial velocity and a quadratic equation that describes its motion. To find the projectile’s height above the ground after 2 seconds, we can simply plug in the value of t=2 into the given equation h(t) = -16t² + 176t.

A projectile is thrown upward with an initial velocity of 176 ft/sec. After t seconds, its height h(t) above the ground is given by the function h(t) = -16t² + 176t. To find the projectile's height above the ground after 2 seconds, substitute t = 2 into the function:

h(2) = -16(2)² + 176(2)

h(2) = -64 + 352

h(2) = 288

Therefore, the projectile's height above the ground after 2 seconds is 288 feet.

Your question is incomplete, but most probably your full question was

A projectile is thrown upward with an initial velocity of 176 ft/sec. After t seconds, its height h(t) above the ground is given by the function h(t) = -16t^2 + 176t. What is the projectile’s height above the ground after 2 sec?