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Exit Ticket A baker has 30(5)/(8) kilograms of flour in his store. If he uses 23(3)/(5) kilograms of it, how many kilograms of flour does he have left? 7(1)/(20) 7(1)/(8) 7(1)/(40) 7(5)/(24)

User Coryan
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Final answer:

To solve the question, the mixed numbers of flour must be converted to improper fractions, find a common denominator, subtract, and then convert back to a mixed number. The remaining flour, after the subtraction is performed, is (9/10) kilograms, which is not listed in the provided options.

Step-by-step explanation:

The question at hand is a subtraction problem in Mathematics involving mixed numbers, where we need to determine the amount of kilograms of flour left after a baker uses a portion of it. The baker starts with 30(5/8) kilograms of flour and uses 23(3/5) kilograms.

To find the remaining flour, we perform the subtraction:
30(5/8) - 23(3/5). Since these are mixed numbers with different denominators, we need to first convert them to improper fractions and find a common denominator before subtracting. After performing the subtraction, we will convert the result back into a mixed number to find out how many kilograms are left.

  • Convert mixed numbers to improper fractions: 30(5/8) becomes (245/8) and 23(3/5) becomes (118/5).
  • Find a common denominator, which is 40 in this case, and convert the fractions: (245/8) becomes (980/40) and (118/5) becomes (944/40).
  • Subtract the fractions: (980/40) - (944/40) = (36/40) or (9/10) after simplification.
  • Convert the improper fraction back to a mixed number: (9/10) is already in simplest form, so the mixed number is 0 remainder (9/10), or just (9/10) kilograms.

Therefore, after using 23(3/5) kilograms of flour, the baker has (9/10) kilograms of flour left, which is not among the provided options and indicates a possible misinterpretation or typo in the question or choices.

Learn more about Subtracting Mixed Numbers

User Arshid Dar
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