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Phs of two functions, f(x) and g(x), are giv f(x)=|x-5|+6 g(x)=(1)/(3)x+(17)/(3)

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Final Answer:

The point of intersection of the functions
\(f(x)\) and
\(g(x)\) occurs at
\(x = 4\), and their respective values at this point are
\(f(4) = 7\) and
\(g(4) = 7\).

Step-by-step explanation:

To find the point of intersection, set
\(f(x)\) equal to
\(g(x)\) and solve for
\(x\):


\[|x - 5| + 6 = (1)/(3)x + (17)/(3).\]

For
\(x < 5\), the equation becomes:


\[-(x - 5) + 6 = (1)/(3)x + (17)/(3),\]

which simplifies to
\(x = 4\).

For
\(x \geq 5\), the equation becomes:


\[(x - 5) + 6 = (1)/(3)x + (17)/(3),\]

which also simplifies to
\(x = 4\).

Evaluate
\(f(4)\) and
\(g(4)\) to find the y-coordinates:


\[f(4) = |4 - 5| + 6 = 7,\]


\[g(4) = (1)/(3)(4) + (17)/(3) = 7.\]

Therefore, the functions intersect at the point
\((4, 7)\), indicating that both functions yield the same y-value at this x-value.

User Rushabh Dave
by
7.9k points