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How many total atoms are there in 19.3 g of hydrazine (N_{2}*H_{2})

How many total atoms are there in 19.3 g of hydrazine (N_{2}*H_{2})-example-1
User Ori Wasserman
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1 Answer

11 votes
11 votes

Answer:


3.87*10^(23)atoms

Explanations:

Given the following parameters

Mass of hydrazine = 19.3 grams

Determine the moles of hydrazine


\begin{gathered} moles\text{ of N}_2H_2=\frac{mass}{molar\text{ mass}} \\ moles\text{ of N}_2H_2=(19.3)/(30.02928) \\ moles\text{ of N}_2H_2=0.6423moles \end{gathered}

According to the Avogadro's constant


1mole\text{ of a substance}=6.02*10^(23)atoms
\begin{gathered} atoms\text{ of N}_2H_2=0.643*6.02*10^(23) \\ atoms\text{ of N}_2H_2=3.87*10^(23)atoms \end{gathered}

Therefore the total atoms that are there in 19.3 g of hydrazine is 3.87 * 10^23 atoms

User Assaf Stone
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