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(x^(4)+7x^(3)-11x^(2)-138x-86)/(x-4) Enter the quotient (without the remainder ).

User CodingFrog
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1 Answer

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Final Answer:

The quotient, without the remainder, for the expression (x^4 + 7x^3 - 11x^2 - 138x - 86)/(x - 4) is x^3 + 11x^2 + 33x + 238.

Step-by-step explanation:

Perform long division by dividing x^4 + 7x^3 - 11x^2 - 138x - 86 by (x - 4).

Identify the term that, when multiplied by (x - 4), results in x^4, which is x^3.

Multiply (x - 4) by x^3 and subtract the result from x^4 + 7x^3 - 11x^2 - 138x - 86.

Bring down the next term, 7x^3, and repeat the process.

Continue this process until all terms are exhausted.

The final quotient, without the remainder, is x^3 + 11x^2 + 33x + 238.

User ISS
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