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Using the following data to answer the questions. x (degrees): 0, 90, 180, 270, 360, y: 0, 3, 0, -3, 0, Using your sinusoidal regression model, what is the estimated y-value for 45 degrees?

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Using the sinusoidal regression model, the estimated y-value for 45 degrees is 2.12

How to find estimated y-value?

To estimate the y-value for 45 degrees using a sinusoidal regression model, we first need to fit the provided data points to such a model. The given data points are:

x (degrees): 0, 90, 180, 270, 360

y: 0, 3, 0, -3, 0

A sinusoidal function can generally be represented as:


\[ y = A \sin(Bx + C) + D \]

where:

A = amplitude,

B = frequency,

C = phase shift, and

D = vertical shift.

Convert x-values to radians:


\[ x_{\text{radians}} = (\pi)/(180) * x_{\text{degrees}} \]

For instance,
\( 0^\circ \),
\( 90^\circ \),
\( 180^\circ \),
\( 270^\circ \), and
\( 360^\circ \) in radians are 0,
\( (\pi)/(2) \),
\( \pi \), \(
(3\pi)/(2) \), and
\( 2\pi \) respectively.

It was found that parameters A, B, C, and D that best fit the data.

Predict for 45 degrees:


\[ x_{\text{predict}} = (\pi)/(180) * 45^\circ = (\pi)/(4) \]

Then use the fitted sinusoidal function to find y for
\( x_{\text{predict}} \).

Given the nature of the data (which resembles a sine wave), start by fitting a sine function to these points and then use the model to estimate the y-value for 45 degrees.

With these parameters, the function was then used to predict the y-value for 45 degrees, resulting in the value of approximately 2.12.

User MrW
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