Final answer:
The question deals with probabilities involving drawing cards and applying Venn diagrams and conditional probabilities. The calculations include P(C|A) and P(A|B ∩ C)) values and determine that no two events (A, B, C) are mutually exclusive.
Step-by-step explanation:
The student's question is addressing the concept of probability using Venn diagrams and conditional probabilities. Let A be 'the card we draw has value greater than 8', B be 'the card we draw has an even value', and C be 'the card we draw is a face card'.
Cards with a value greater than 8 (A) include: 9, 10, J, Q, K, and ace. Cards with an even value (B) are: 2, 4, 6, 8, and 10. Face cards (C) are: J, Q, K.
To solve part b, P(C|A) is the probability of C given A. We see that there are 6 cards in A and 3 of them are face cards. So, P(C|A) ≈ 0.5000 (3/6).
For part c, P(A|(B ∩ C)) is the probability of A given the card is neither even (B) nor a face card (C). Only the ace fits these criteria, so when the only outcome is the ace, P(A|(B ∩ C)) = 1.0000.
For part d, by evaluating the overlap of the sets, no two pairs from A, B, and C are mutually exclusive because all pairs have elements in common. For example, the 10 is both greater than 8 (A) and an even card (B).