Final answer:
To find the probability of the sample mean being within $600 of the population mean for samples of size 40 and 80, calculate the standard error of the mean for each sample size and use the Central Limit Theorem and z-table to determine the probabilities.
Step-by-step explanation:
The probability that the sample mean, x ˉ, is within $600 of the population mean can be found by using the Central Limit Theorem which tells us about the sampling distribution of the sample mean.
For a population with a mean (μ) of $71,800 and a standard deviation (σ) of $5000, and a sample size (n) of 40, we first need to calculate the standard error of the mean using σ/√n. Then, we use the z-table to find the probability that lies within ±$600 of the population mean. Similarly, this process is repeated for a sample size of 80 to find the corresponding probability.
For n = 40:
Calculate the standard error (SE) of the mean: SE = σ/√n = $5000/√40
Calculate the z-scores for ±$600 from the mean: Z = ±$600/SE
Look up these z-scores on the z-table to find the probabilities.
Subtract the lower probability from the higher probability to find the total probability.
Repeat the steps with n = 80 to find the corresponding probability.