Final Answer:
a) Null hypothesis
: The average scores of students in the first and second sections of David Anderson's introductory accounting classes are equal. Alternative hypothesis
: There is a significant difference in the average scores between the two sections.
b) The test statistic for the hypothesis test is
.
c) At a significance level
of 0.01, the critical value for a two-tailed test is
. Since
, we fail to reject the null hypothesis. There is not enough evidence to conclude that there is a significant difference in the average scores between the two sections.
Step-by-step explanation:
- To formulate the hypotheses, we set up the null hypothesis (\(H_0\)) as the assumption that there is no difference in the average scores between the two sections:
. The alternative hypothesis
suggests that there is a significant difference:
.
- To compute the test statistic, we use the formula
where
and
are the sample means,
and
are the sample standard deviations, and
and
are the sample sizes. Plugging in the values, we find
.
- Using a critical value approach at a significance level
of 0.01 for a two-tailed test, the critical values are
(obtained from a t-table). Since
, we fail to reject the null hypothesis.
This implies that the observed difference in average scores is not statistically significant at the 0.01 level, and we do not have enough evidence to conclude that there is a significant disparity between the two sections.