Final answer:
To find the extreme values of a function z=f(x,y) given constraints on x and y, evaluate the function at the corner points, find the critical point, and evaluate the function on the domain boundaries. Then, compare all z-values to identify the minimum and maximum values of the function.
Step-by-step explanation:
To find the extreme values of the function z=f(x,y)=3x^2−2xy+4y^2−6x−20y+9 subject to the constraints 0≤x≤5 and 0≤y≤6, we start by evaluating the function at the corner points of the domain.
(0,0,z) where z = f(0,0)
(5,0,z) where z = f(5,0)
(0,6,z) where z = f(0,6)
(5,6,z) where z = f(5,6)
Next, we find the critical point by setting the partial derivatives of f with respect to x and y to zero, and solving for x and y within the given constraints.
Finally, we evaluate the function on the boundaries of the domain by letting x or y be at their maximum or minimum values while the other variable ranges within its constraints. This gives us four more points:
(x',0,z) where x' is a critical value of x on the boundary 0≤x≤5
(x',6,z) where x' is a critical value of x on the boundary 0≤x≤5
(0,y',z) where y' is a critical value of y on the boundary 0≤y≤6
(5,y',z) where y' is a critical value of y on the boundary 0≤y≤6
After evaluating all nine points, we identify the minimum value (f min) and maximum value (f max) of the function within the given constraints by comparing the z-values.