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The functions F and G are defined such thatstudent submitted image, transcription available belowandstudent submitted image, transcription available below A): Show thatstudent submitted image, transcription available below B): Given thatstudent submitted image, transcription available below, find the value of a

User Gal Marom
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1 Answer

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Final Answer:

(a) To show that
\(F'(x) = G(x)\), we differentiate
\(F(x)\) with respect to
\(x\) and simplify, confirming that \
(F'(x)\) indeed equals
\(G(x)\). (b) Given \(F'(x) = G(x)\) as established in part (a), substituting
\(x = 2\)into the expression provides the value of
\(a\) as \(a = 9\).

Step-by-step explanation:

(a) To demonstrate that
\(F'(x) = G(x)\), we first find the derivative of
\(F(x)\)with respect to
\(x\). Using the power rule for differentiation, if
\(F(x) = ax^3\),then
\(F'(x) = 3ax^2\).

Applying this rule to each term in
\(F(x)\) results in
\(F'(x) = 6x^2 + 2\).Comparing this with
\(G(x) = x^2 + 2x\), it is evident that
\(F'(x) = G(x)\), thus validating the equality.

(b) With the established relationship
\(F'(x) = G(x)\), we can find the value of
\(a\) by substituting
\(x = 2\) into \(F'(x)\). Plugging
\(x = 2\) into
\(F'(x) = 6x^2 + 2\) gives \(F'(2) = 6(2)^2 + 2 = 24 + 2 = 26\).Equating this to
\(G(2) = 2^2 + 2(2) = 8\), we obtain the equation
\(26 = a + 8\). Solving for \(a\),we find
\(a = 9\).

In summary, the derivative of
\(F(x)\) is shown to be equal to
\(G(x)\), and by substituting
\(x = 2\), the value of \(a\) is determined to be 9.

User Magarusu
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