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[Technology] MORE SKI WAX From Chapter 14, Exercise 58□, Bjork Larsen was trying to decide whether to use a new racing wax for cross-country skis. He decided that the wax would be worth the price if he could average less than 55 seconds on a course he knew well, so he planned to study the wax by racing on the course 8 times. His 8 race times were 56.3, 65.9,50.5,52.4,46.5,57.8,52.2, and 43.2 seconds. Should he buy the wax? Explain by performing an appropriate hypothesis test.

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Answer:

Based on the given race times, Bjork Larsen should not buy the new racing wax for cross-country skis if his criterion is to average less than 55 seconds on the course.

Step-by-step explanation:

To determine whether Bjork Larsen should buy the new racing wax for cross-country skis, we can perform a hypothesis test.

The null hypothesis (H0) would be that the average race time is equal to or greater than 55 seconds, while the alternative hypothesis (Ha) would be that the average race time is less than 55 seconds.

Let's calculate the average race time and perform the hypothesis test using a significance level of 0.05.

The 8 race times are: 56.3, 65.9, 50.5, 52.4, 46.5, 57.8, 52.2, and 43.2 seconds.

Step 1: Calculate the sample mean

The sample mean (x) is calculated by summing up all the race times and dividing by the number of races (8 in this case).

x = (56.3 + 65.9 + 50.5 + 52.4 + 46.5 + 57.8 + 52.2 + 43.2) / 8 = 51.95 seconds

Step 2: Calculate the sample standard deviation

The sample standard deviation (s) measures the variability of the race times.

s = √[ (56.3 - 51.95)² + (65.9 - 51.95)² + (50.5 - 51.95)² + (52.4 - 51.95)² + (46.5 - 51.95)² + (57.8 - 51.95)² + (52.2 - 51.95)² + (43.2 - 51.95)² ] / (8 - 1)

s ≈ 7.32 seconds

Step 3: Perform the hypothesis test

We can perform a one-sample t-test to compare the sample mean to the hypothesized mean of 55 seconds.

The t-value is calculated as: t = (x - μ) / (s / √n)

Where:

x is the sample mean

μ is the hypothesized mean (55 seconds)

s is the sample standard deviation

n is the sample size (8)

t = (51.95 - 55) / (7.32 / √8)

≈ -1.49

Using a t-table or statistical software, we can find the critical t-value for a one-tailed test with a significance level of 0.05 and 7 degrees of freedom (n - 1 = 8 - 1 = 7).

The critical t-value is approximately -1.895.

Since the calculated t-value (-1.49) is not less than the critical t-value (-1.895), we fail to reject the null hypothesis.

This means that there is not enough evidence to conclude that the average race time is less than 55 seconds.

Therefore,

Based on the given race times, Bjork Larsen should not buy the new racing wax for cross-country skis if his criterion is to average less than 55 seconds on the course.

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