Final Answer:
(a) The 75% confidence interval for p is [0.54, 0.66], and the 95% confidence interval is [0.51, 0.69].
(c) When constructing 95% CIs for 20 samples, the percentage containing p may be close to 95%, but not exactly.
(d) True: Confidence level must match sample proportion for CI guarantee. If Sample 21 had the same proportion as Sample 6, its 75% CI would be wider.
Step-by-step explanation:
(a) For the 75% confidence interval, we use the critical value 1.150. The margin of error (ME) is calculated as ME = critical value * standard error. For a 75% confidence interval, ME = 1.150 * sqrt(0.60 * (1 - 0.60) / 120) ≈ 0.06. Therefore, the interval is [0.53 - 0.06, 0.53 + 0.06], which simplifies to [0.54, 0.66].
For the 95% confidence interval, with a critical value of 1.960, ME = 1.960 * sqrt(0.60 * (1 - 0.60) / 120) ≈ 0.08. The interval is [0.53 - 0.08, 0.53 + 0.08], which simplifies to [0.51, 0.69].
(c) The statement that best fits the scenario is: When constructing 95% confidence intervals for 20 samples of the same size from the population, the percentage of the samples that contain the population proportion should be close to 95%, but it may not be exactly 95%.
(d) The correct statements are: To guarantee that a confidence interval will contain the population proportion, the level of confidence must match the sample proportion. If there were a Sample 21 of size n=160 with the same sample proportion as Sample 6, then the 75% confidence interval for Sample 21 would be wider than the 75% confidence interval for Sample 6.