Final Answer:
a. H0: μ ≤ 3 (Null hypothesis)
H1: μ > 3 (Alternative hypothesis)
b. Test statistic = 1.29
c. Critical value = 1.729
d. P-value ≈ 0.102
e. The p-value is greater than the chosen value of α, so we do not reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than 3.
Step-by-step explanation:
a. To test whether the claim that people read more than three books on average holds, the null hypothesis (H0) states that the mean number of books read (μ) is less than or equal to 3. The alternative hypothesis (H1) suggests that the mean number of books read is greater than 3.
b. The test statistic, calculated using the formula
Test statistic = Sample mean − Population mean / Standard deviation / √Sample size , is 1.29. This value indicates how many standard deviations the sample mean is away from the population mean.
c. With a significance level (α) of 0.05 for a one-tailed test, the critical value for rejecting the null hypothesis lies at 1.729, obtained from the z-table or a statistical calculator.
d. The calculated p-value is approximately 0.102. This value represents the probability, under the assumption that the null hypothesis is true, of observing a sample mean as extreme as the one obtained or more extreme. Since the p-value is greater than α (0.05), we fail to reject the null hypothesis.
In summary, based on the given data and using a significance level of 0.05, we do not have sufficient evidence to conclude that the mean number of books read per month is greater than 3. The p-value suggests that the observed sample mean is not significantly different from the claimed average of more than three books per month, thus failing to reject the null hypothesis.