Final answer:
The organization can state with 95% confidence that the true population proportion of the local population living within two miles of a grocery store is in the interval [0.616, 0.864]. The lowest likely proportion is 0.616.
Step-by-step explanation:
To calculate the proportion (p-hat) and the 95% confidence interval for the proportion of the local population living within two miles of a grocery store, we count the number of "Yes" responses in the sample.
Number of "Yes" responses = 37
Sample size (n) = 50
p-hat = Number of "Yes" responses / Sample size = 37 / 50 = 0.74
Using the critical value for a 95% confidence level (z* = 1.960):
Margin of Error = z* * sqrt(p-hat * (1 - p-hat) / n)
Margin of Error = 1.960 * sqrt(0.74 * (1 - 0.74) / 50)
Calculate the margin of error and apply it to find the lower and upper bounds of the 95% confidence interval:
Lower bound = p-hat - Margin of Error
Upper bound = p-hat + Margin of Error
Finally, the organization can state with 95% confidence that the true population proportion of the local population living within two miles of a grocery store is in the interval [0.616, 0.864]. The lowest likely proportion is 0.616.