Question

Find the area inside one leaf of the rose: r=6sin(5θ)

Answer 1

The calculated area inside one leaf of the rose: r=6sin(5θ) is 2.24

How to determine the area inside on leaf of the rose

From the question, we have the following parameters that can be used in our computation:

We have:

r = 6sin(6θ)

First we have to find the limits:

r = 0

6sin(6θ) = 0

θ = nπ/6

n = 0 to n = 1

θ = 0 to θ = π/6

So, we have

`\text{Area = } \int\limits^(\pi/6)_0 {6\sin(5\theta)\\ \, d\theta`

Integrate and evaluate

Area = 2.24

Hence, the area inside one leaf of the rose: r = 6sin(5θ) is 2.24