Final answer:
The student's question on housing inventory damage can be addressed using a Poisson distribution, where p represents the probability of damage. The calculation for P(D) involves using the Poisson formula for different values of p and noting the trend as p changes.
Step-by-step explanation:
To address the problem of housing inventory damage using a Poisson distribution, we assume that 'damage' is a rare event occurring with a known average rate in a large population of houses. When estimating the Probability of Damage P(D), we can use the Poisson formula: P(X=k) = (e-λλk)/k!, where λ is the average rate of damage (the product of the number of trials n and the probability of a single damage event p), and k is the number of damage events we're interested in finding the probability for (in this case, we are interested in at least one damage event so k ≥ 1).
For different levels of probability p, keeping in mind the number of trials n is large, we can estimate P(D) as follows:
- For p = 0.01, find λ by multiplying n and p, then use it to calculate P(D).
- Repeat this process with p = 0.05, 0.10, and 0.20.
- Discuss the trend observed as p increases; typically, as p increases, P(D) will increase up to a point before it starts decreasing again, due to the nature of the Poisson distribution.
Remember, the approximation of the binomial distribution with a Poisson distribution is valid when n is large and p is small.