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If y varies directly with x and y =2 when x=4 find the value of y when x =11

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Explanation:

If \(y\) varies directly with \(x\), it means there exists a constant \(k\) such that \(y = kx\).

Given that \(y = 2\) when \(x = 4\), you can use this information to find the constant \(k\):

\[2 = k \times 4\]

Solving for \(k\), you get \(k = \frac{2}{4} = \frac{1}{2}\).

Now that you have the constant \(k\), you can use it to find the value of \(y\) when \(x = 11\):

\[y = \frac{1}{2} \times 11\]

\[y = \frac{11}{2}\]

So, when \(x = 11\), the value of \(y\) is \(\frac{11}{2}\) or 5.5.

User Daniel Quinlan
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