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Factorise fully v^2 + 5v -6

User Polyhedron
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3 votes

Answer:

\((v + 6)(v - 1)\).

Explanation:

To factorize the quadratic expression \(v^2 + 5v - 6\), we can find two numbers whose product is the product of the coefficient of the quadratic term (1) and the constant term (-6) and whose sum is the coefficient of the linear term (5).

In this case, the numbers are 6 and -1 because \(6 \times (-1) = -6\) and \(6 + (-1) = 5\).

So, the factorization is \((v + 6)(v - 1)\).

User Jack Averill
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