The completed table in the question can be presented as follows;
![\begin{tabular} \cline{1-5}&&Empire State Building&& \\ \cline{1-5}Original Image & Actual Height (in feet) & 1,450 & 1,450 & 1,450 \\\cline{1-5}Reduced Image & Model Height (in blocks) & 145& \underline{145} & \underline{145}\\\cline{1-5} & Scale factor & \underline{1 : 10} & \underline{1 : 10} & \underline{ 1 : 10} \\\cline{1-5}\end{tabular}]()
The scale factor is the number of times the size of the image is larger than the size of the original object
Whereby the original size of the Empire State Building is 1,450 feet and the size of the reduced image, which is the Model Height is 145 feet, we get;
Scale factor = Reduced Image Height/(Original Image Height)
Reduced Image Height/(Original Image Height) = 145/1450
145/1450 = 1/10
Scale factor is; 1/10 = 1 : 10
The table can therefore, be completed as follows;
Model Height for the two adjacent blank cells under the Empire State Building = 145 feet
Scale Factor for for the three cells in the Scale Factor row = 1 : 10
Please see the completed table with the required values underlined
The possible table, obtained from a similar table on the website can be presented as follows;
![\begin{tabular} c \cline{1-5}&&Empire State Building&& \\ \cline{1-5}Original Image & Actual Height (in feet) & 1,450 & 1,450 & 1,450 \\\cline{1-5}Reduced Image & Model Height (in blocks) & 145&& \\\cline{1-5} & Scale factor & & &\\\cline{1-5}\end{tabular}]()