Answer:
12
Explanation:
we have four odd numbers 89, 95, 99, 173, and two even numbers 132 and 166.
the cases where the sum of three numbers is even is: e/e/e and o/o/e.
e/e/e isn't possible since there are only two even numbers.
the other alternative is o/o/e, so we take 2 odd numbers and 1 even number.
this is equivalent to 4C2 × 2C1 = 6 × 2 = 12
so, there are 12 subsets.