The escape speed of an electron launched from the surface of a glass sphere depends on the charge of the sphere, the electric field strength, and the mass of the electron.
To calculate the escape speed of an electron from a charged spherical surface, we will use the formula for the electrical potential energy and equate it to the kinetic energy of the electron. Considering the diameter of the glass sphere is 1.3 cm and the charge is 5.0 nC, we first calculate the potential (V) at the surface of the sphere using V=kQ/R, where R is radius of the sphere, Q is the charge, and k is Coulomb's constant (8.99×109 N·m2/C2).
The potential energy (U) of the electron at the surface of the sphere is then U=eV, where e is the charge of an electron (1.60×10-19 C). Finally, to find the escape speed (v), we set the kinetic energy (1/2 mev2) equal to the potential energy (U), and solve for v. This can be done by using the formula v=√(2U/me).
The complete question is- what is the escape speed of an electron launched from the surface of a 1.3- cm -diameter glass sphere that has been charged to 5.0 nc ? explain the formula.