To calculate the energies and wavelengths of the three lowest rotational transitions emitted by a NaCl molecule, you can use the formula E = (h^2 / 8 * pi^2 * I) * J(J + 1). Using the given equilibrium separation of NaCl and the masses of the atoms, you can calculate the moment of inertia and then use it in the formula to find the energies and wavelengths. The radiations would be found in the region of the electromagnetic spectrum determined by the wavelength.
To calculate the energies and wavelengths of the three lowest rotational transitions emitted by a NaCl molecule, we can use the formula:
E = (h^2 / 8 * pi^2 * I) * J(J + 1)
where E is the energy, h is Planck's constant, pi is a mathematical constant, I is the moment of inertia of the molecule, and J is the quantum number representing the rotational state.
Using the given equilibrium separation of NaCl (0.236 nm) and the masses of sodium and chlorine atoms, we can calculate the moment of inertia and then use it in the formula to find the energies of the three lowest rotational transitions. The wavelengths of these transitions can be determined using the equation:
λ = c / ν
where λ is the wavelength, c is the speed of light, and ν is the frequency. Finally, to determine the region of the electromagnetic spectrum in which these radiations would be found, we can use the relationship between wavelength and electromagnetic spectrum.
The complete question is- Calculate the energies and wavelengths of the three lowest rotational transitions emitted by molecule NaCl. In what region of the electromagnetic spectrum would these radiations be found?
Note that here the two components of the molecule have different masses. The equilibrium separation of NaCl is equal to 0.236 nm.)