Question

s plane flies 200m/h along a bearing of 320 deg. the air iss moving with a wind speed of 60 mi/h along a bearing of 190 deg. find the plane's resultant velocity (speed and bearing) by adding these two velocity vectors

Answer 1

To find the plane's resultant velocity, convert the units and add the velocity vectors of the plane and the wind. The resultant speed is 1809.34 m/h and the resultant bearing is 510 deg.

To find the plane's resultant velocity, we need to add the velocity vectors of the plane and the wind. First, let's convert the velocities to the same units.

The plane's speed is given as 200 m/h, and the wind speed is given as 60 mi/h. Converting the wind speed to m/h, we get:

60 mi/h * (1.61 km/mi) * (1000 m/km) * (1 h/60 min) = 1609.34 m/h

Now, we can add the velocity vectors using vector addition:

Resultant speed = plane speed + wind speed = 200 m/h + 1609.34 m/h = 1809.34 m/h

Resultant bearing = angle of the wind + angle of the plane = 320 deg + 190 deg = 510 deg

Therefore, the plane's resultant velocity is 1809.34 m/h along a bearing of 510 deg.