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the minimum frequency for photoelectric emission in copper is 1.1 1015 hz. find the maximum energy of the photoelectrons (in electronvolts) when light of frequency 1.5 1015 hz is directed on a copper surface.

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The maximum energy of the photoelectrons when light of frequency 1.5 x 10^15 Hz is directed on a copper surface is approximately 0.62 eV.

The maximum energy of the photoelectrons can be found using the equation E=hf, where E is the energy, h is Planck's constant (6.63 x 10^-34 J·s), and f is the frequency of the light. To find the maximum energy of the photoelectrons when light of frequency 1.5 x 10^15 Hz is directed on a copper surface, we can substitute the values into the equation:

E = (6.63 x 10^-34 J·s)(1.5 x 10^15 Hz)
Calculating this, we find that the maximum energy of the photoelectrons is approximately 9.94 x 10^-19 J, or 0.62 eV (electronvolts) when rounded to two decimal places.

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