Answer:
500
105
Explanation:
This question would be solved using a simultaneous equation
let
a = number of adults who bought the ticket
b = number of students who bought the ticket
c = number of senior citizens who bought the ticket
a + b + c = 670 eqn 1
10a + 4b + 3c = 5615 -- eqn 2
If 65 senior citizen bought the ticket, substitute for c in equation 1 and 2
a + b + 65 = 670
a + b = 670 - 65
a + b = 605 eqn 3
10a + 4b + 3(65) = 5615
10a +4b = 5420 eqn 4
multiply equation 3 by 10 to derive equation 5. Subtract eqn 4 from eqn 5
10a + 10b = 6050 eqn 5
-
10a + 4b = 5420 eqn 4
= 6b = 630
b = 105
Students who bought the ticket are 105
Substitute for b in eqn 3
a + 105 = 605
a = 500
Adults who bought the ticket are 500