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4.6.1 the peak temperature t, as mea- sured in degrees fahrenheit, on a july day in new jersey is the gaussian (85, 10) random variable. what is p/t > 100), p[t < 60), and p[70 < t < 100)?

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Therefore, the probability of the temperature is between 70 and 100 degrees Fahrenheit is 0.8664.

To find these probabilities

The conventional normal distribution (Z) will be employed. With a mean of 0 and a standard deviation of 1, the standard normal distribution is a Gaussian distribution. Any Gaussian random variable X can be made standard by deducting its mean (µ) and dividing the result by its standard deviation (σ):

Z = (X - µ) / σ

The probability can be found using a calculator or the standard normal distribution table once the random variable has been normalized.

P[T > 100]

First, we standardize the value 100:

Z = (100 - 85) / 10 = 1.5

P(Z > 1.5) ≈ 0.9332, according to the conventional normal distribution table. Consequently, there is a about 0.9332 chance that the temperature is higher than 100 degrees Fahrenheit.

P[T < 60]

First, we standardize the value 60:

Z = (60 - 85) / 10 = -2.5

P(Z < -2.5) = 0.0062, according to the conventional normal distribution table. Consequently, there is a 0.0062 chance that the temperature is below 60 degrees Fahrenheit.

P[70 < T < 100]

By deducting the two probabilities we previously computed, we may determine this probability:

P[70 < T < 100] = P(T < 100) - P(T < 70)

P(T < 100) = 0.9332 (calculated above)

To find P(T < 70), we standardize the value 70:

Z = (70 - 85) / 10 = -1.5

P(Z < -1.5) = 0.0668, according to the conventional normal distribution table. P(T < 70) ≈ 0.0668 as a result.

P[70 < T < 100] = 0.9332 - 0.0668 ≈ 0.8664

User Andrej Jurkin
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