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a charge of 71 nc is located at the origin. what is the net electric flux through a cube of dimensions 1m x 1m x 1m which has its corner at the origin and the bottom surface along the x-y plane?

User Elyptikus
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The net electric flux through a cube of dimensions 1m x 1m x 1m with a charge of 71 nc located at the origin can be found by summing up the electric flux through each face of the cube. The electric flux through each face can be calculated using the formula Flux = E * A * cos(theta), where E is the electric field, A is the area of the face, and theta is the angle between the electric field and the normal to the face. The electric field is directly proportional to the charge and inversely proportional to the square of the distance between the charge and the face of the cube.

The net electric flux through a cube can be found by summing up the electric flux through each face of the cube. In this case, the cube has dimensions of 1m x 1m x 1m and is centered at the origin. The charge of 71 nc is located at the origin.

Since the charge is located at the origin, the distance between the charge and each face of the cube is the same. Therefore, the electric flux through each face of the cube will be equal in magnitude.

The electric flux through a face of the cube can be calculated using the formula:

Flux = E * A * cos(theta)

where E is the electric field, A is the area of the face, and theta is the angle between the electric field and the normal to the face.

In this case, the electric field E is directly proportional to the charge and inversely proportional to the square of the distance between the charge and the face of the cube. The area of each face is 1 square meter.

Since the electric field is perpendicular to two opposite faces of the cube, the angle theta is 90 degrees. Therefore, the electric flux through each of these faces is zero.

The electric flux through the other four faces can be calculated using the formula:

Flux = E * A

Since the electric flux through each face of the cube will be equal in magnitude, the total electric flux through the cube is four times the flux through one face.

Finally, the net electric flux through the cube can be calculated by subtracting the flux through the two faces perpendicular to the electric field from the total flux through the cube.

User Nico Erfurth
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