Question

write the structural formula of the organic product for the given reaction between an alkyne and an alkyl halide the alkyne

Answer 1

When an alkyne (CC) reacts with an alkyl halide, it typically undergoes an addition reaction. The alkyl halide can add to one of the carbon atoms of the alkyne, forming a new carbon-carbon bond.

An example reaction between ethyne (CC) and methyl iodide (CH3I):

`\[ \text{CC} + \text{CH3I} \rightarrow \text{CH3CCCH3} \]`

So, in the above , one of the carbon atoms in ethyne (CC) reacts with the methyl group (CH3) from methyl iodide (CH3I) to form the product 2-methyl-2-butyne, which can be written as
`\(\text{CH3CCCH3}\).` So, if one has an alkyne and alkyl halide, one can substitute them into this general pattern to draw the structural formula of the product.

See text below

Write the structural formula of the organic product for the following reaction between an alkyne and an alkyl halide. (The alkyne group is shown, and should be entered, as ''CC'', without the triple bond.) Product structural formula (formatting counts: enter C before associated H atoms; subscript numbers) (eg., CH3CH2CH2OCHCHCH3)