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What is the internal energy of 5.00 mol of O2 gas at 22°C?

User Castaldi
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Final answer:

The internal energy of 5.00 mol of O2 gas at 22°C is determined using the equation for an ideal diatomic gas, E = (5/2)RT per mole, with R as the gas constant and T as the absolute temperature in Kelvin.

Step-by-step explanation:

To calculate the internal energy of 5.00 mol of O2 gas at 22°C,

we will consider the gas as an ideal diatomic gas.

For an ideal diatomic gas, the molar internal energy (E) can be given by the equation E = (5/2)RT per mole,

where R is the ideal gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin.

The temperature in Kelvin is calculated by adding 273.15 to the Celsius temperature, which gives us T = 22 + 273.15 = 295.15 K.

For 5.00 mol of O2, the internal energy E is:

E = 5.00 mol × (5/2) × 8.314 J/(mol·K) × 295.15 K.

When you calculate this, you find the internal energy for the O2 gas under the given conditions.

User Amol Sawant
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