Question

Calculate the number of moles of carbon dioxide gas in this fire extinguisher. Gas type CO2 temperature: 212 K pressure: 4.55 atm Volume: 3.5L

Answer 1

0.9154 mol CO₂

Procedure

To solve this question you will need to use the ideal gas law

PV=nRT

Data

P=4.55 atm

V= 3.5 L

T= 212 K

R=0.082057 L⋅atm⋅K⁻¹⋅mol⁻¹

Solve for n

`n=(PV)/(RT)=\frac{4.55\text{ atm }3.5\text{L mol }\degree\text{K}}{0.082057\text{ L.atm }212\degree\text{K}}=0.9154\text{ mol }`