Question

Can you please help me out with a question

Answer 1

`J.24`

Step-by-step explanation

we have a rigth triangle, then

Let

leg1=radius= 7

leg2=QP

hypotenuse= radius+18=25

now, we can use the Pythagorean theorem:

Pythagorean theorem, the geometric theorem that states the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse

`a^2+b^2=c^2`

hence, replace

`\begin{gathered} 7^2+QP^2=25^2 \\ 49+QP^2=625 \\ \text{subtract 49 in both sides} \\ 49+QP^2-49=625-49 \\ QP^2=576 \\ \text{square rot in both sides} \\ \sqrt[\square]{QP^2}=\sqrt[\square]{576} \\ QP=24 \end{gathered}`

so, the answer is

`J.24`

I hope this helps you