Main Answer:
Mass of oxygen = 96.0 g.
In Ca₃(PO₄)₂, with 64.0 g of calcium, the calculated mass of oxygen is 96.0 g, determined by applying the molar ratio and the molar mass of oxygen.
Step-by-step explanation:
In Ca₃(PO₄)₂, the molar ratio between calcium (Ca) and oxygen (O) is 3:8. Given that the mass of calcium (Ca) is 64.0 g, we can calculate the mass of oxygen (O) by applying the molar ratio and determining the molar mass of oxygen. First, find the moles of calcium using its molar mass. Next, use the mole ratio from the chemical formula to find the moles of oxygen. Finally, convert the moles of oxygen to grams using the molar mass of oxygen.
In this case, the molar mass of calcium (Ca) is 40.08 g/mol. So, 64.0 g of calcium is equivalent to 1.598 moles of calcium (64.0 g / 40.08 g/mol). With the mole ratio from the chemical formula Ca₃(PO₄)₂ (3 moles of Ca to 8 moles of O), the moles of oxygen are calculated as 4.264 moles (1.598 moles Ca * (8 moles O / 3 moles Ca)). Finally, convert moles of oxygen to grams using the molar mass of oxygen (16.00 g/mol), resulting in 96.0 g of oxygen (4.264 moles O * 16.00 g/mol).
This process ensures the accurate determination of the mass of oxygen in the given sample, considering the stoichiometry of the compound and the molar masses of the elements involved.