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Use planck's constant to determine the energy in joules per photon of radiation of frequency 7.39*10^15

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Final answer:

The energy of a photon with a frequency of 7.39×1015 Hz is calculated using Planck's constant and is 4.89734×10-18 J per photon.

Step-by-step explanation:

To determine the energy in joules per photon of radiation with a frequency of 7.39×1015 Hz, we can use the equation E = hf, where h is Planck's constant and f is the frequency of the radiation.

Using Planck's constant, h = 6.626 × 10-34 J·s, and the given frequency, f = 7.39 × 1015 Hz (1/s), we can calculate the energy as follows:

E = (6.626 × 10-34 J·s) × (7.39 × 1015 Hz)

E = 4.89734 × 10-18 J per photon

User Jon Carlstedt
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